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X^2+0.75X=0
a = 1; b = 0.75; c = 0;
Δ = b2-4ac
Δ = 0.752-4·1·0
Δ = 0.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.75)-\sqrt{0.5625}}{2*1}=\frac{-0.75-\sqrt{0.5625}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.75)+\sqrt{0.5625}}{2*1}=\frac{-0.75+\sqrt{0.5625}}{2} $
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